Hint: The same
old hint – perpendicular bisector of chord pass through center.
Solution:
The segment cuts off by the required circle is a
chord, and the perpendicular bisector of the chord must pass through center. So
let construct the perpendicular bisector by constructing the line pass through
O perpendicular to the given segment. That gives us the point J. The point J
bisect the chord, and the chord must have length CD, so just find the midpoint
of CD (name it E), and then draw a circle with center J with length CE, that
gives us the point K, the circle with center O and radius OK give us the
solution.
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