Hint: You only
need another point C so that it is equal distance from A and from B.
Solution: This is
a very simple problem (after all this is just level 1) – the solution is as
follow – you construct the other vertex C of the equilateral triangle. The
point C must have AC = AB, so it must lie on the circle with center A and
radius AB. The point C must also have BA = BC, so it must lie on the circle
with center B and radius BA, therefore the solution is as follow
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