Hint: Think ratios.
Solution: First construct the ray AB, and
let the outer tangent line intersect AB at O. Now OA:OB should be (radius of A:
radius of B). To find such point O, we use the similar triangle NAO and MBO.
Once we found the point O, we need to find a point C on circle A such that OCA
is a right angle. Now we leverage another fact, angle subtended by the diameter
on a circle is the right angle, so we construct the midpoint P of O and A, draw
the circle with center P and radius PA, so the intersection between the circle
would give us the point C and we are done.
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